zn+1=({Δ}2+2≈4⊕4){πxπxπ}zn c sum prior
zn+1=({Δ}2+2≈4∨4){πxπxπ}zn c sum prior
zn+1=({Δ}2+2≈4∧4){πxπxπ}zn c sum prior (perfect)
zn+1=zn{(Δ}≐(2+2≈4∧4})≐{π≐π≐π}+cΣ sum prior
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Foreword: This work is 7 years in the making. 7 years of continued deduction, reaching the final step, around a month ago, defining how we...
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